Convergence of the orthogonal iteration

We saw that $Q_k$ converges to $Q$, and $T_k=Q_k^{H}A{Q}_k$ converges to an upper triangular matrix.

The rate of convergence is not straightforward to derive.

Here is a sketch of a proof. Start with

$$A^k=X{\Lambda }^k{X}^{-1}.$$

Span of $Q_k[1:i]$ converges to span of $X[1:i]$ = span of $Q[1:i].$ The convergence rate is given by

$$\left|\frac{{\lambda }_{i+1}}{{\lambda }_i}\right|$$

Proposition 1: Convergence of orthogonal iteration

The norm of the block $T_k[i+1:n,1:i]$ decays like

$$|\frac{{\lambda }_{i+1}}{{\lambda }_i}{|}^k.$$

$\square$

Proposition 1: Convergence of the Ritz eigenvalues

Assume that we start with a random $Q_0$ with $r$ columns. In that case, $T_k$ has dimension $r\times r$. The eigenvalues of $T_k$ are called Ritz eigenvalues. The $i$th Ritz eigenvalue converges to ${\lambda }_i$ with rate

$$|\frac{{\lambda }_{r+1}}{{\lambda }_i}{|}^k$$

$\square$

Let’s go back to the case of $Q_0=I$ and $T_k$ of size $n\times n$. Consider a case where ${\lambda }_j\gg {\lambda }_{j+1}$. Then we have the following block structure for $T_k$.

$$\left(\begin{array}{cc}\ast & \ast \\ ϵ& \ast \end{array}\right)$$

We converge quickly to a $2\times 2$ block upper triangular matrix.

More generally if we have sufficient separation between eigenvalues, i.e., $|{\lambda }_i|\gg |{\lambda }_{i+1}|,$ then convergence to an upper triangular matrix is very fast.